Question

If a 65kg woman is driving off a 10 meter platform, what is her speed as she hits the water?

Answer 1

more information is required to answer this question like her initial speed(or velocity),acceleration,frictional force(if any) etc

Answer 2

No it isn't. Assuming no air resistance, you just use: \[v^2=u^2+2as\]Her initial vertical velocity is zero so this term disappears, you know s=10m and a=9.81ms^-2

Answer 3

the woman is driving off the platform..how can her inital velocity be zero?

Answer 4

I agree with bendt ans
its correct

Answer 5

Her initial vertical velocity is zero, not her horizontal velocity.

Answer 6

before driving off the plateform her speed is zeroo

Answer 7

At the instant she leaves the platform, the vertical component of her velocity vector is zero.

Answer 8

mmm...but isnt the final speed affected by both vertical and horizontal components?

Answer 9

horizontal component doesnot play any role in vertical velocity

Answer 10

Yes, Vids93, but that's not what the question's asking. Think of her walking off the platform.

Answer 11

i see the qs says what is the 'speed' as the woman hits the water!

Answer 12

Yes but it clearly doesn't want you to take into account the horizontal velocity because, as you said, you would need more information.

Answer 13

Thanks bendt..:)

Answer 14

No problem.

Answer 15

What would the u^2 stand for?

Answer 16

Initial velocity.

Answer 17

Ok thank you!