Question

x^2-4 FIND THE HOLES
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x+1

Answer 1

is it "holes" or "poles"? if it is poles this thing has a pole at -1 because that is where the denominator is 0. i have never heard of it being called a "hole"

Answer 2

usually called vertical asymptote

Answer 3

yea vertical asymptote

Answer 4

or horizontal

Answer 5

ok vertical asymptote set denominator = 0 and solve

Answer 6

so long as the numerator is not also zero there, you have a vertical asymptote

Answer 7

SeeRed -- have you graphed this function?

Answer 8

in this case
\[\frac{(x+2)(x-2)}{x+1}\]

Answer 9

^yes

Answer 10

denominator is 0 if x = -1 so it will have a vertical asymptote there. no horizontal asymptote because the degree of the numerator is bigger than the degree of the denominator

Answer 11

do you need to find the 'slant' asymptote as well?

Answer 12

no i have the the answer. thak for your help

Answer 13

welcome