For the domain, -2≤x≤3, what is the range of the function f(x)=|2x+1| ?

Question

For the domain, -2≤x≤3, what is the range of the function f(x)=|2x+1|  ?

owlfred · Answer

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anonymous · Answer

the smallest the absolute value of something can be is 0, so you know the range starts at 0

anonymous · Answer

replace x by 3 and get 7, so that is the largest it can be.  range : {0,7}

anonymous · Answer

i guess it is worth mentioning that you should also replace x by -2, but in that case you only get 3, which is smaller than 7

anonymous · Answer

when x = 1/2, f(x) = 0
when x = 3, f(x) = 7;
hence the range 0 to 7

anonymous · Answer

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mathteacher1729 · Answer

NOTE: we can't just assume the range starts at zero because it's an absolute value function.  What if we specified the domain to be (10,11)?  

Here is a graph. remember RANGE = "lowest value of y to highest value of y that the graph attains". 

Hope this helps. :)