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Solve |1-2x| > x+1
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Graph \[y_1 = |1-2x|\] and \[y_2=x+1\] Find the intervals where \(y_1\) is above \(y_2\), and that's that. :)
without graphing?
|1-2x| = (1-2x) AND (-1+2x) 1-2x > x+1 -1+2x>x+1 0 > 3x 3x > 2 0>x x > 2/3
ugh..... that left is off
Nicely done! Here is the pic to tie it all together. :)
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-1+2x > x+1 ; -x and +1 x > 2
(-inf,0) U (2,inf)
another way to do this is to square both sides to find the critical points in this case 0 and 2 and to test for x <0, 0<x<2, and x>2 .
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