Question

Solve |1-2x| > x+1

Answer 1

Graph \[y_1 = |1-2x|\] and \[y_2=x+1\] Find the intervals where \(y_1\) is above \(y_2\), and that's that. :)

Answer 2

without graphing?

Answer 3

|1-2x| = (1-2x) AND (-1+2x)

1-2x > x+1 -1+2x>x+1
0 > 3x 3x > 2
0>x x > 2/3

Answer 4

ugh..... that left is off

Answer 5

Nicely done! Here is the pic to tie it all together. :)

Answer 6

-1+2x > x+1 ; -x and +1
x > 2

Answer 7

(-inf,0) U (2,inf)

Answer 8

another way to do this is to square both sides to find the critical points in this case
0 and 2 and to test for x <0, 0<x<2, and x>2 .