Question

Amistre64, it's me again. Need help with an exponent again!

Answer 1

didja try yelling at it?

Answer 2

jI even grounded it and took away it's cell phone and it won't cooperate! I can't understand...it works with my 15 year old daughter!

Answer 3

\[-3/2\times 2^{-2/9}\]

Answer 4

dont punish them it makes it worse. They now think math is bad if you truly want to help arrange extra help and talk to the teacher

Answer 5

Did you see my expression I need to solve?

Answer 6

i see it

Answer 7

we wanna derive it?

Answer 8

No I need to figure out what it's = to.

Answer 9

2^-2/9 equals what?

Answer 10

\[\frac{-3}{2*2^{2/9}}\]

Answer 11

\[\frac{-3}{2^{(9/9 + 2/9)}}\]

Answer 12

we good so far?

Answer 13

yes, I got that far. I know that answer, but what i got wasn't right according to them Like they know any better! Who are they to tell me I am always wrong!?

Answer 14

; )

Answer 15

:)
\[\frac{-3}{2^{11/9}}\]
\[\frac{-3}{\sqrt[9]{2^{11}}}\]

Answer 16

\[2^{11} \iff 2^{9}*2^{2}\]

\[\sqrt[9]{2^9.2^2}\iff \sqrt[9]{2^9}.\sqrt[9]{2^2}\]
\[\frac{-3}{2\sqrt[9]{2^2}}\]

Answer 17

\[\sqrt[9]{2^4}*\sqrt[9]{2^5} = \sqrt[9]{2^9}\iff 2\] right?

Answer 18

yes, I remember that one from the s thing earlier! Yay me!

Answer 19

\[\frac{-3}{2\sqrt[9]{2^4}}*\frac{\sqrt[9]{2^5}}{\sqrt[9]{2^5}} = \frac{-3\sqrt[9]{64}}{4}\]

Answer 20

i typoed it dint i lol

Answer 21

9rt(2^2) not equal 9rt(2^4) lol

Answer 22

Actually we lucked out cuz they are leaving the radical in the denominator! The answer to the whole problem is cbrt 2 - 3/2ninth root of 4, just what you said! I am not surprised you got it right!

Answer 23

yay!! i was dreading having to retype thaqt lol

Answer 24

\[\sqrt[3]{2}- 3/2\sqrt[9]{4}\]

Answer 25

Again and again and again, thank you.

Answer 26

yw :)