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Mathematics 11 Online
OpenStudy (anonymous):

Help! please! attach file

OpenStudy (anonymous):

OpenStudy (anonymous):

first one is 15

OpenStudy (anonymous):

the other is J 3

OpenStudy (anonymous):

can u show me step?

OpenStudy (anonymous):

hoe u get 3 and 15

OpenStudy (anonymous):

for the first one: log base 4 of 4^15 simply says: what power do you raise 4 to in order to get 4^15.

OpenStudy (anonymous):

And so, obviously if you raise 4 to the 15th power, you get 4^15

OpenStudy (anonymous):

\[\text{Log}[2,9x+5]=2+\text{Log}\left[2,x^2-1\right] \]\[\text{Log}[2,9x+5]-\text{Log}[2,x{}^{\wedge}2-1]= 2 \]\[\text{Log}\left[\frac{a}{b}\right]\text{= }\text{Log}[a]-\text{Log}[b]\]\[\text{Log}\left[2,\frac{9x+5}{x^2-1}\right]=2\]\[(\text{Log}[b,x]=k )\to \left(b^k= x\right) \]\[2^2-\frac{9x+5}{x^2-1}=0\]\[\frac{-9-9 x+4 x^2}{-1+x^2}=0 \]\[\frac{((-3+x) (3+4 x))}{-1+x^2}=0\]\[x=3 \]

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