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Mathematics 13 Online
OpenStudy (anonymous):

Determine the derivative of this: y = tan^2(x^3)

OpenStudy (anonymous):

How do we use the chain rule here?

OpenStudy (anonymous):

first you get 3x^2 from x^3 than u do tan^2 that is 2tan^2(x^3) than tan that is sec^2(x^3)

OpenStudy (anonymous):

so the answer is 6x^2 tan^2(x^3) sec^2(x^3)

OpenStudy (anonymous):

hoops not right tan^2 bit is 2tan(x^3)

OpenStudy (anonymous):

6x^2 tan(x^3) sec^2(x^3)

OpenStudy (anonymous):

hope it is clear

OpenStudy (anonymous):

\[\tan ^2(x^3)\] <-- would you mind doing it in this format.

OpenStudy (anonymous):

\[y' = 2(tanx)(\sec^2x)(x^3)(3x^2)\]

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