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Determine the derivative of this: y = tan^2(x^3)
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How do we use the chain rule here?
first you get 3x^2 from x^3 than u do tan^2 that is 2tan^2(x^3) than tan that is sec^2(x^3)
so the answer is 6x^2 tan^2(x^3) sec^2(x^3)
hoops not right tan^2 bit is 2tan(x^3)
6x^2 tan(x^3) sec^2(x^3)
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hope it is clear
\[\tan ^2(x^3)\] <-- would you mind doing it in this format.
\[y' = 2(tanx)(\sec^2x)(x^3)(3x^2)\]
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