Question

i need to express tanx secx in terms of sinx

Answer 1

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Answer 2

\[\tan(x) = \frac{\sin(x)}{\cos(x)}\] and \[\sec(x) = \frac{1}{\cos(x)}\]

Now multiply those together and cancel. :)

Answer 3

Oh, sorry not cancel... You'll have to use the identity \[\sin^2(x) + \cos^2(x)=1\] in the denominator.

Answer 4

still not sure how this works

Answer 5

i don't see a final answer