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Find the derivative of the function using the product rule (x)(sqrt(x^2+5))
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u'v+uv'
you'll need the chain rule for the sqrt(x^2+5) term as well
\[\sqrt{{x ^2}+5}+x ^{2}/\sqrt{x ^{2}+5}\]
yep that looks right
i got that but can i simplify it anymore?
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yeah you can multiply top and bottom by sqrt(x^2+5)
the first term I mean
(2x^2+5)/(sqrt(x^2+5))
i mean i have to substitute my x in for the equation of the tangent line is it a good idea to just leave that like that?
less computation if you simplify it a little further
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\[x ^{2}/\sqrt{x ^{2}+5}\]so i added it and got
sorry 2x^2 +5 for numerator
sorry 2x^2 +5 for numerator
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