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Mathematics 16 Online
OpenStudy (anonymous):

atachment file

OpenStudy (anonymous):

OpenStudy (anonymous):

\[8.2^{n-3}=42.5\] \[ln(8.2^{n-3})=ln(42.5)\]

OpenStudy (anonymous):

\[(n-2)ln(8.2)=ln(42.5)\] \[n-2=\frac{ln(42.5)}{ln(8.2)}\]

OpenStudy (anonymous):

\[n=\frac{ln(42.5)}{ln(8.2)}+2\]

OpenStudy (anonymous):

need the next one? works the same i think

OpenStudy (anonymous):

step 1. take the log of both sides

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

step 2 pull out the exponent as a multiplier

OpenStudy (anonymous):

step 3 now that everything is on the ground floor use algebra. i will write it

OpenStudy (anonymous):

\[2.1^{t-5}=9.2\]

OpenStudy (anonymous):

frist one how u get (n-2)

OpenStudy (anonymous):

because i made a typo. replace the 2 by a 3!

OpenStudy (anonymous):

i typed it in wrong at the start. 2 should be 3. all other steps are the same

OpenStudy (anonymous):

i will write the next one \[2.1^{t-5}=9.2\] step 1 take the log of both sides \[ln(2.1^{t-5})=ln(9.2)\]

OpenStudy (anonymous):

step 2 pull the t - 5 out front as a multipier \[(t-5)ln(2.1)=ln(9.2)\]

OpenStudy (anonymous):

ste 3 divide both sides by ln(2.1) we are trying to get t by itself \[t-5=\frac{ln(9.2)}{ln(2.1)}\]

OpenStudy (anonymous):

step 4 add 5 to both sides \[t=\frac{ln(9.2)}{ln(2.1)}+5\]

OpenStudy (anonymous):

done

OpenStudy (anonymous):

u great ,thank

OpenStudy (anonymous):

welcome!

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