Mathematics
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OpenStudy (anonymous):
atachment file
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OpenStudy (anonymous):
OpenStudy (anonymous):
\[8.2^{n-3}=42.5\]
\[ln(8.2^{n-3})=ln(42.5)\]
OpenStudy (anonymous):
\[(n-2)ln(8.2)=ln(42.5)\]
\[n-2=\frac{ln(42.5)}{ln(8.2)}\]
OpenStudy (anonymous):
\[n=\frac{ln(42.5)}{ln(8.2)}+2\]
OpenStudy (anonymous):
need the next one? works the same i think
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OpenStudy (anonymous):
step 1. take the log of both sides
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
step 2 pull out the exponent as a multiplier
OpenStudy (anonymous):
step 3 now that everything is on the ground floor use algebra. i will write it
OpenStudy (anonymous):
\[2.1^{t-5}=9.2\]
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OpenStudy (anonymous):
frist one how u get (n-2)
OpenStudy (anonymous):
because i made a typo. replace the 2 by a 3!
OpenStudy (anonymous):
i typed it in wrong at the start. 2 should be 3. all other steps are the same
OpenStudy (anonymous):
i will write the next one
\[2.1^{t-5}=9.2\]
step 1 take the log of both sides
\[ln(2.1^{t-5})=ln(9.2)\]
OpenStudy (anonymous):
step 2 pull the t - 5 out front as a multipier
\[(t-5)ln(2.1)=ln(9.2)\]
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OpenStudy (anonymous):
ste 3 divide both sides by ln(2.1) we are trying to get t by itself
\[t-5=\frac{ln(9.2)}{ln(2.1)}\]
OpenStudy (anonymous):
step 4 add 5 to both sides
\[t=\frac{ln(9.2)}{ln(2.1)}+5\]
OpenStudy (anonymous):
done
OpenStudy (anonymous):
u great ,thank
OpenStudy (anonymous):
welcome!