And you WANT another problem?

Question

anonymous · Answer

Let me attach the one I am doing now that doesn't have an answer attached to it.

amistre64 · Answer

now that I know what im looking at yes lol

anonymous · Answer

attachment

amistre64 · Answer

thats the exact same one; only with a sqrt7 lol

anonymous · Answer

ok, there you go.  Let me try to work it too and see what I come up with and then you can let me know where I'VE SCREWED UP

anonymous · Answer

I know it's the same one basically, but it doesn't matter, cuz I keep getting them wrong consistently!

anonymous · Answer

cheat like crazy: use the computer.

amistre64 · Answer

we know the integral goes to $$s+s^{-1/2}$$ tho so thats a start

anonymous · Answer

43 to go!

amistre64 · Answer

when we use the bottom limit we get:

$$1-2 = -1 right?$$

amistre64 · Answer

$$s -2s^{-1/2}$$ i meant to type

amistre64 · Answer

$$s - \frac{2}{\sqrt{s}}+1 \rightarrow s=\sqrt{7}$$ is?

amistre64 · Answer

$$\sqrt{7} -\frac{2}{\sqrt[4]{7}}+1$$

amistre64 · Answer

essentally its just:
$$F(\sqrt{7})-F(1)$$
$$F(s) = s-{2\over\sqrt{s}}$$

anonymous · Answer

ok, you went WAYYYYYY too fast for me!  I just got F(x)!  Let me work this and see if I can get what you got, ok?

amistre64 · Answer

ok.....

anonymous · Answer

i just successfully got sqrt7 - 2/ 4th root 7 for F(sqrt7).  That's where I am in the figuring.  Now for F(1)...

amistre64 · Answer

yay!!

amistre64 · Answer

and for shorthand:

4rt(7) is easier to read thru

anonymous · Answer

ok, then here's my answer:  Let me get the equation thing and do it that way.

anonymous · Answer

$$\sqrt{7}-2/\sqrt[4]{7}+1$$

amistre64 · Answer

thats it

anonymous · Answer

Is that right?

anonymous · Answer

YAY!!! Couldn't have done it without you!  Did I tell you I have been working on this particular problem (#31) since noon today?

amistre64 · Answer

yeah, :)

amistre64 · Answer

lets try one that is not 'exactly' the same lol

anonymous · Answer

ok, so does this mean, now that you have taught me how to send you my problems, that you are willing to look at any of them I cannot do on my own (as long as you are online and available with the time?)?

amistre64 · Answer

yeah, ow that i aint gotta read your mind it should be easier ;)

anonymous · Answer

That particular problem will have all the same types with the same integrand.  That's the point, to let ua do the same ones over and over to get the precise idea of how top do them.  I will see if the next problem is different and let you know, ok?

amistre64 · Answer

interactmath.com is just like your math program except its free.

you can practice on it all you like.

amistre64 · Answer

http://interactmath.com/PlayerPractice.aspx?bookId=92382&chapterId=6§ionId=1&exerciseId=656&type=3