Amistre64 can you help me again?
\[22xe ^{x ^{2}}/\sqrt{e ^{x ^{2}}}\]
ok .... and this is a part of?
I need to find what it equals. I know what the answer is again, but again do not know how they got it.
want a screen shot?
let me see the problem to get an better view of what you need; yes screen shot
who is thinking up these things lol
I told you.,,it's the same guy that thinks he's smarter than me! Telling me I'm wrong all the time!! Humph!
\[\frac{22x.e^{x^2}}{\sqrt{e^{x^2 }}}\]
and you wanna know how they get their answer
yes
just index laws
lets clean it up some: \[\frac{22x.b}{\sqrt{b}}\] thats easier to see right? \[\frac{22x.b}{\sqrt{b}}*\frac{\sqrt{b}}{\sqrt{b}}=\frac{22x.b.b^{1/2}}{b}\] right?
does \({b\over b}\) cancel to 1?
leaves us: \[22x.b^{1/2}\] and we said \(b = e^{x^2}\) so rewrite it: \[22x.e^{(1/2)x^2}\]
yes but l;et me try to catch up...had to go away to give some medicine to my son. Let me scroll up to look at what you've typed.
You are the best...again thank you! You turned on my light bulb!
lol...youre welcome
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