Question

Find the center, vertices, foci, and slope of the asymptotes for the hyperbola.
(x-4)^2/16 - (y+4)^2/16 = 1

Answer 1

u can use wolfram and check he graph out

Answer 2

http://www.wolframalpha.com/input/?i=%28x-4%29^2%2F16++-++%28y%2B4%29^2%2F16+%3D+1

Answer 3

center(4,-4)

verts are a distance of 4 from teh center to get: (8,-4) (0,-4)

Answer 4

your bottoms ar ethe same whih means we get a distance of 4sqrt(2) for the foci

foci = (4+4sqrt(2),-4) and (4-4sqrt(2),-4)

Answer 5

and slope of asymps are 1 and -1

Answer 6

jeezzz thanks again lol!!!