Why is the vertex or parabola y=(x-3)^2+2 (3, 2)?
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youre correct the answer is (3,2)
But Why?
becasue the definition of vertex is where the bend cuts the axis at
oh sorry i thought it said what. because whenever you have a parabola equation you take the number in () which is -3 and change the sign and leave the number outside of () which is 2 the same so it would be 3,2
the vertex is halfway between the foci and the directix; so its the shortest distance between them and lies on the axis of symmetry
I understand that when x=3 the y would be 2 but how would you get the 3 other than just trying to make the 3 to 0?
Sorry if my question is sort of confusing. I'm asking more for the concept behind it.
the concept is a geometric one
that is just how the formula works. whatever # is after x is just the oppisite there isnt really a reson behind it you just kind of have to do it.
okay thank your for your help; both of you. Is there any way for me to give you a rating of some sort? I'm sorry, this is my first time here.
you just click the blue "good answer" by our names :) and no problem
hit f5 to refresh your browser and you should see a 'good answer' button next to our names
here is an idea.
the smallest \[x^2\] can be is 0
it is 0 if x = 0
the smallest \[(x-3)^2\] can be is zero and it is zero if x = 3
so the smallest \[(x-3)^2+2\] can be is 2, and it is 2 if x = 3 that is why the vertex is (2,3)
28 to go lardamercy!
thank you Satellite
welcome
hello myininaya
hey :) i'm thinking about showing him something once i figure out if i can do this something that i'm about to do i know that made no sense lol
right! this vertex stuff is not as hard as it is made out to be. i can show it to people who know basically no math at all. now i am going to take my measly less than half of amistre's medals (jealous, me?) and go to bed. some people have to work
lol later
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