Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Why is the vertex or parabola y=(x-3)^2+2 (3, 2)?

OpenStudy (owlfred):

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

OpenStudy (smurfy14):

youre correct the answer is (3,2)

OpenStudy (anonymous):

But Why?

OpenStudy (amistre64):

becasue the definition of vertex is where the bend cuts the axis at

OpenStudy (smurfy14):

oh sorry i thought it said what. because whenever you have a parabola equation you take the number in () which is -3 and change the sign and leave the number outside of () which is 2 the same so it would be 3,2

OpenStudy (amistre64):

the vertex is halfway between the foci and the directix; so its the shortest distance between them and lies on the axis of symmetry

OpenStudy (anonymous):

I understand that when x=3 the y would be 2 but how would you get the 3 other than just trying to make the 3 to 0?

OpenStudy (anonymous):

Sorry if my question is sort of confusing. I'm asking more for the concept behind it.

OpenStudy (amistre64):

the concept is a geometric one

OpenStudy (smurfy14):

that is just how the formula works. whatever # is after x is just the oppisite there isnt really a reson behind it you just kind of have to do it.

OpenStudy (anonymous):

okay thank your for your help; both of you. Is there any way for me to give you a rating of some sort? I'm sorry, this is my first time here.

OpenStudy (smurfy14):

you just click the blue "good answer" by our names :) and no problem

OpenStudy (amistre64):

hit f5 to refresh your browser and you should see a 'good answer' button next to our names

OpenStudy (anonymous):

here is an idea.

OpenStudy (anonymous):

the smallest \[x^2\] can be is 0

OpenStudy (anonymous):

it is 0 if x = 0

OpenStudy (anonymous):

the smallest \[(x-3)^2\] can be is zero and it is zero if x = 3

OpenStudy (anonymous):

so the smallest \[(x-3)^2+2\] can be is 2, and it is 2 if x = 3 that is why the vertex is (2,3)

OpenStudy (anonymous):

28 to go lardamercy!

OpenStudy (anonymous):

thank you Satellite

OpenStudy (anonymous):

welcome

OpenStudy (anonymous):

hello myininaya

myininaya (myininaya):

hey :) i'm thinking about showing him something once i figure out if i can do this something that i'm about to do i know that made no sense lol

OpenStudy (anonymous):

right! this vertex stuff is not as hard as it is made out to be. i can show it to people who know basically no math at all. now i am going to take my measly less than half of amistre's medals (jealous, me?) and go to bed. some people have to work

myininaya (myininaya):

lol later

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!