Given sinθ = -3/4 and θ is in quadrant 4, find the following:

cosθ

tanθ

sin (-θ)

cos (-θ)

Question

Given sinθ = -3/4 and θ is in quadrant 4, find the following:

cosθ

tanθ

sin (-θ)

cos (-θ)

anonymous · Answer

attachment

anonymous · Answer

draw the picture

anonymous · Answer

sin is the opposite over the hypotenuse

anonymous · Answer

and use pythagorus to find the unknown side ( which turns out to be sqrt(7) )

anonymous · Answer

so now we have the triangle we can read of the values

anonymous · Answer

cos(theta) = sqrt(7) / 4

anonymous · Answer

What is sqrt? I haven't learned that...

anonymous · Answer

tan(theta ) = -3 / sqrt(7) , note: tan isneagtive in the 4th quadrant

anonymous · Answer

sqaure root lol

anonymous · Answer

$$\sqrt{7} ?$$ , you must know

anonymous · Answer

Oh okay thank you lol I got confused

anonymous · Answer

ow, sin(-theta) - -sin(theta ) because sin is an odd function 

so sin(- theta ) = 3/4

anonymous · Answer

and cos(-theta) = cos(theta) , because cos is even ,

so cos(-theta) = sqrt(7) / 4

anonymous · Answer

thank you SOOOOO much! You're a big help. I really appreciate it!