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Mathematics 10 Online
OpenStudy (anonymous):

how do you find magnitude?

OpenStudy (anonymous):

of which?

OpenStudy (anonymous):

a vector?

OpenStudy (anonymous):

i think it is of two vectors.. im not sure

OpenStudy (anonymous):

if a,b are two vectors and angle between them is x then the magnitude's square is a^2+b^2+2ab cos x

OpenStudy (anonymous):

ohh ok thanks

OpenStudy (anonymous):

or if you're just given one vector let's say {a,b,c} then to find the magnitude of the vector then magnitude = \[\sqrt{(a^2 + b^2 +c^2)}\]

OpenStudy (anonymous):

this is possible only when the vectors are mutually perpendicular

OpenStudy (anonymous):

thank you

myininaya (myininaya):

remember we were finding maginture of like -3 and it was 3 then the magintude of a is |a| |a|=sqrt(a^2) what about we went from (x1,y1) and (x2,y2) it was sqrt{(x1-x2)^2+(y1-y2)^2)

OpenStudy (anonymous):

for any inclined angle between them u have to add a cos x term. when the angle is 90 then the cos term vanishes nd u get a result like sqrt(a^2+b^2)

OpenStudy (anonymous):

myininaya....u gave the distance between two vectors not the magnitude of the resultant...

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