Question

solve dis one pls 3^lnx=2^lny if x' nd y' r solution for it den wats x'

Answer 1

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Answer 2

x= y^(ln2/ln3)

Answer 3

3^lnx = 2^lny
take log to base 3 both side then
lnx = log(base3)(2^lny)
x = e^( log(base3)(2^lny))
x = 2^(lny/ln3)

Answer 4

i didnt get u bro

Answer 5

were do u have difficulty

Answer 6

i hav doubt rite frm first step its 3 power lnx.....

Answer 7

as i mentioned the steps involved are
1) take log to base 3 of both sides
2)u get lnx
now for example consider ln(r) = t ,then r = exponential(t) i.e, r=e^t
3)then u have x = e^(log(base 3) (2^lny))
now as per property of logarithms log(base x)y = lny/lnx
or in general log(base x)y = (log(base z)y)/(log(base z)x)
so u get x =e^( (ln(2^lny)) /ln(3))
so this can be solved and written as x = 2^(ln(y) / ln(3))

i hope u got it.