Find the answer. B needs to be by itself. (a+b)/2c = b+d

Question

anonymous · Answer

You want to solve for $b$?

anonymous · Answer

yes!

anonymous · Answer

And show your work, please!

anonymous · Answer

OK. Start by multiplying both sides by $2c$ to get rid of the denominator. So, we will have $a+b=(b+d)2c$. Opening the parenthesis gives $a+b=2bc+2cd$. Since we're trying to solve for $b$, we should combine all terms with $b$ in one side and everything else on the other side. That gives $b-2bc=2cd-a$. Take $b$  as a common factor in the left hand side, you get $b(1-2c)=2cd-a$. Finally divide both sides by $1-2c$ you get $b=\frac{2cd-a}{1-2c}$.

anonymous · Answer

b = (a-2*c*d)/(2*c-1)

anonymous · Answer

cross multiply 
then a+b =2c(b+d)
then take b containing term on one side and rest on other side
so b(2c-1) = a-2cd
now divide both side by (2c-1)
so u get
b= (a-2cd)/(2c-1)

anonymous · Answer

(a+b)/2c = b=d

2bc + 2cd = a + b   .................. (multiply both side by 2c)

2bc - b = a - 2cd ...................... (changing side of b)

b ( 2c - 1) = a - 2cd 

b = (a-2cd) / (2c - 1)

anonymous · Answer

Everyone had good answers! Thanks, and I agree with them.

anonymous · Answer

Well they all are actually the same :)