Question

Calculate Tan 0

Answer 1

0

Answer 2

Using Triangle with angle 0 ,Hypotenuse 12, and bottom Leg 10

Answer 3

Use pythagoras to find opposite leg
12 squared - 10 squres = 44
so root 44
therefore tan theta = (in your calculator) INV TAN root44/10

Answer 4

I am assuming it is tan theta not tan zero as that would be something altogether different.

Answer 5

tan0=sin0/cos0=0

Answer 6

sin0=0
sin30=1/2
sin60=sqrt3/2
sin90=1
cos0=1
cos30=sin60=sqrt3/2
cos60=sin30=1/2
cos90=0
tan0=sin0/cos0=0
tan30=1/sqrt3
tan60=sqrt3
tan90=sin90/cos90=1/0\[\infty\]

Answer 7

i think this can be helpful to you

Answer 8

tan90=sin90/cos90=1/0=∞

Answer 9

Korcan, you have posted some pretty good things here but I still think we are looking at theta as opposed to zero.

Answer 10

hmm

Answer 11

Look at info regarding hypotenuse and leg length

Answer 12

is 0 in radians or degree

Answer 13

tan 0 = sin 0 / cos 0 = 0/1= 0

Answer 14

The length of the legs are:
hypotenuse=12 , bottom leg=10.
For the 3rd leg we have:\[\sqrt{12^2-10^2} = \sqrt{44}\]

\[\tan(\theta)=\frac{OppositeLegLength}{AdjacentLegLength}\]

So, if theta is opposite the 3rd leg , then:\[\tan(\theta)=\sqrt{44}/10\]
Otherwise, theta is opposite the bottom leg, then: \[\tan(\theta)=10/\sqrt{44}\]

Answer 15

Going further -

If theta is opposite the 3rd leg, then:
\[\tan(\theta)=\frac{\sqrt{44}}{10} = \frac{\sqrt{4*11}}{10}=\frac{\sqrt{4}\sqrt{11}}{10}=\frac{2\sqrt{11}}{10}=\frac{\sqrt{11}}{5}\]

Otherwise, theta is opposite the bottom leg, then:
\[\tan(\theta)=\frac{5}{\sqrt{11}}\]

If your original problem had a diagram, you can see whether theta is opposite the bottom leg or opposite the 3rd leg .