Question

solve for x:
log$2(x+1)+log$2(3x-5)=log$2(5x-3)+2

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

(x+1)(3x-5) = 4(5x-3)

Answer 3

okay......can you keep going?

Answer 4

3x^2 -2x -5 = 20x -12
3x^2 - 22x +7 = 0

Answer 5

does the last line factor into (x-7)(3x-1)?

Answer 6

yes

Answer 7

x = 7 or 1/3
now substitute both these values into ur initial eqn to double check

Answer 8

okay and on the first line you wrote 4(5x-3).....how did you get the four? 2^2?

Answer 9

yes 2 can be written as log 4 to base 2

Answer 10

and then we use log a + log b =log (ab)

Answer 11

thanks you. thanks were i kept going wrong. The solutions both work. :)

Answer 12

no prob miss

Answer 13

can i ask one more thing? if you are solving for x and you take the square root to isolate x, do you include both the positive and negative answers?

Answer 14

yes

Answer 15

like lets say x^2 = k
then x = k AND -k

Answer 16

in some special situations we can neglect the negative answer..bt generally it is essential to consider both

Answer 17

thanks you!