Question

\[{ 1 \over R} = {1 \over R1} + {1 \over R2} \]

Answer 1

Solve the equation for the indicated variable.

Answer 2

guess it depends on the indicated variable.

Answer 3

\[{1 \over R}\] ? lol

Answer 4

are you solving for \[R\]
\[R_1\] or \[R_2\]?

Answer 5

no. i'm sorry. it's R1

Answer 6

whew. ok

Answer 7

haha. work with me satellite. :p

Answer 8

subtract \[\frac{1}{R_2}\] from both sides, take the reciprocal

Answer 9

\[\frac{1}{R}-\frac{1}{R_2}=\frac{1}{R_1}\]

Answer 10

\[{1 \over R} - {1 \over R2} = {1 \over R1} ? \]

Answer 11

\[\frac{R_2-R}{RR_2}=\frac{1}{R_1}\]

Answer 12

haha. same thing! this is good!

Answer 13

now flip everything to get
\[\frac{RR_2}{R_2-R}=R_1\]

Answer 14

where did you come up with the last one?

Answer 15

the one before the last... not flipping but the previous one

Answer 16

oh i had 1/R and wanted R. just flip it

Answer 17

oh previous one. ok hold on

Answer 18

\[\frac{1}{a}-\frac{1}{b}=\frac{b}{ab}-\frac{a}{ab}\] yes? common denominator is ab and i have to build up the fractions

Answer 19

then you subtract to get
\[\frac{b-a}{ab}\]

Answer 20

clear?

Answer 21

no. give me a second. i'm going to write it...

Answer 22

ok if not clear let me know. think of
\[\frac{1}{5}-\frac{1}{3}\]

Answer 23

forgot to close your tag

Answer 24

this:
\[\frac{1}{a}-\frac{1}{b}=\frac{b}{ab}-\frac{a}{ab} \]
is important for me to remember. i am taking note of it. i think it's just that i need to understand this before being able to do these kind of problems. does that sound right from what you are seeing with me?

Answer 25

but i understood

Answer 26

yes, but don't get married to that formula. to add and subtract fraction it is always
\[\frac{a}{bb}\pm\frac{c}{d}=\frac{ad\pm bc}{bd}\]

Answer 27

thanks for confusing me more :p

Answer 28

just in this case the numerators happened to be 1!

Answer 29

that should really not confuse you much. how do you add
\[\frac{2}{3}+\frac{5}{7}\]? it is just
\[\frac{2\times 7 + 3\times 5}{3\times 7}\]

Answer 30

i would rather find the common denominator for the fraction with numbers lol

Answer 31

but you are showing me a more advanced way. i believe i must learn this way to be succesful

Answer 32

in your case it was
\[\frac{1}{R}-\frac{1}{R_2}=\frac{1\times R_2-1\times R}{R\times R_2}\]

Answer 33

so the 1's were eliminated.... then we are left with variables

Answer 34

wtf. that's the easiest way to add fractions that i have seen.

Answer 35

thank you again!
so the:
\[\frac{a}{bb}\pm\frac{c}{d}=\frac{ad\pm bc}{bd} \]
applies to all fractions?