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Mathematics 10 Online
OpenStudy (anonymous):

e^-x=6

OpenStudy (anonymous):

X=-ln6

OpenStudy (anonymous):

in equivelant logarithic form this says \[ln(6)=-x\]so \[x=-ln(x)\]

OpenStudy (anonymous):

what eliza said, not what i said

OpenStudy (anonymous):

\[x=-ln(6)\] is right

OpenStudy (anonymous):

Remember that \[e^k = a \iff ln\ a = k\] So in your case you have k = -x and a = 6. Therefore: \[e^{-x} = 6 \iff ln(6) = -x\]\[\therefore x = -ln(6)\]

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