Question

If 7,500 bacteria, with a growth constant k=0.4, are present 3hrs after beginning the experiment, how many are present 8 hrs later?
a) 24,849 bacteria
b) 2,259 bacteria
c) 610,500 bacteria
d) 184,000 bacteria

Answer 1

i assume the k refers to 'percentage'

Answer 2

7500 = P(1.4)^3

Answer 3

P= 7500/(1.4)^3

X = [7500/(1.4)^3](1.4)^11

Answer 4

the closest number i get to the choices is d, but i cant say for sure that I was right

Answer 5

i see it; e^kt ....

Answer 6

7500 = P.e^(.4*3)

Answer 7

183 ....... so its still D but with more confidence lol

Answer 8

okay thank you