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Mathematics 17 Online
OpenStudy (mathsadness):

A guy pushes off the ground with a force 50% greater than his weight. What is his upward acceleration?

OpenStudy (mathsadness):

please help

OpenStudy (amistre64):

force = mass*acceleration

OpenStudy (mathsadness):

i know....

OpenStudy (anonymous):

Well if his force is 50% more than his mass.. We have force = 1.5(mass)

OpenStudy (mathsadness):

weight does not equal mass.....

OpenStudy (anonymous):

Fair enough.

OpenStudy (amistre64):

weight is a result of mass

OpenStudy (anonymous):

If you prefer then, wieght = mg = 9.8(mass)

OpenStudy (mathsadness):

what is the answer

OpenStudy (anonymous):

42

OpenStudy (mathsadness):

fail

OpenStudy (mathsadness):

9.8 * 1.5

OpenStudy (mathsadness):

enough jokes

OpenStudy (mathsadness):

right???

OpenStudy (anonymous):

force = 1.5(weight) weight = 9.8(mass) force = (mass)(acelleration) Therefore (1.5)(9.8)(mass) = (mass)(acelleration) Therefore acceleration is 1.5 * 9.8 (assuming the mass is in kilos)

OpenStudy (mathsadness):

no cuz then he would accelerate upwards and not decellerate back to the ground

OpenStudy (mathsadness):

it must be negative

OpenStudy (anonymous):

Is this a math problem or a physics problem?

OpenStudy (mathsadness):

and it is weight - 1.5 weight= -0.5 weight= -4.9

OpenStudy (mathsadness):

obviously a physics problem, but it involves math

OpenStudy (mathsadness):

i think the answer is -4.9

OpenStudy (mathsadness):

m

OpenStudy (anonymous):

If it's a physics problem then you have to do the sum of the forces. \[F_{up} - F_{g} = ma\]\[\implies 1.5(F_g) - F_g = ma\]\[\implies .5(F_g) = ma\]\[\implies .5(mg) = ma\]\[\implies a = .5g\] Where g is either 9.8 or 32 depending on whether the mass is in kilos or in slugs.

OpenStudy (mathsadness):

but the acelleration must be negative!!!!!

OpenStudy (mathsadness):

silly!!!

OpenStudy (anonymous):

no. If it was negative he'd never get off the ground. And he'd be travelling into the dirt.

OpenStudy (mathsadness):

nope! negative means he reaches a peak in his jump and doesnt keep going faster into space. duh.

OpenStudy (anonymous):

If you are so confidant.. answer it yourself. I am correct. He only has a negative acceleration once he's stopped pushing and his feet have left the ground. And in that scenario his acceleration will always be -mg.

OpenStudy (mathsadness):

it depends on what part of the jump you are talking about

OpenStudy (anonymous):

once his feet have left the ground it doesn't matter how hard he was pushing. His acceleration will always be -g because gravity is the only force acting on him.

OpenStudy (anonymous):

so I must assume it's talking about his acceleration before he leaves the ground otherwise his force wouldn't make any difference.

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