Consider the following.
f(x)=18x-15/-x^2+1

Determine the value that the function f approaches as the magnitude of x increases. (If you need to use or –, enter INFINITY or –INFINITY, respectively.)

Question

Consider the following. 
 f(x)=18x-15/-x^2+1

Determine the value that the function f approaches as the magnitude of x increases. (If you need to use  or –, enter INFINITY or –INFINITY, respectively.)

anonymous · Answer

anybody can help me?

amistre64 · Answer

the degree of the bottom is larger than the top; so it all goes to .... 0.  i was wrong

anonymous · Answer

why?

anonymous · Answer

nice

anonymous · Answer

is like 1/2,

amistre64 · Answer

18x-15
-------  simple answer is divide everything by the highest x in the bottom
-x^2+1

anonymous · Answer

you dont have to devide, you only divide when the numerador is bigger than the denominator.  2x^2/x for example

amistre64 · Answer

$$\frac{\frac{18x}{x^2}-{15\over x^2}}{{-x^2\over x^2} + {1\over x^2}}$$

anonymous · Answer

but the answer is not infity.

amistre64 · Answer

$${(18/x) - (15/x^2)} = 0$$when x is large

amistre64 · Answer

the answer is 0

anonymous · Answer

ut how you get 0?

amistre64 · Answer

the concept is tp mulitply everything by a useful form of 1; I choose $\frac{1/x^2}{1/x^2}$

anonymous · Answer

oh yeah, the is like the hoz asympt?

amistre64 · Answer

whatever simplifies and still has an 'x' under it; get very very very tiny, for example:

  1              1
--- ;-- ------------  =  .00000...000001 , a very tiny number right?
 x     100000...00000

amistre64 · Answer

it is the horizontal asymptote yes

anonymous · Answer

ok, thx