i know the answer

A model for the data is given by the following.
t=38m+16965/10(m+5000)
Use the model to approximate the mass of an object when the average time for one oscillation is 1.058 seconds. Round your answer to the nearest gram.

Question

i know the answer

A model for the data is given by the following. 
 t=38m+16965/10(m+5000)
Use the model to approximate the mass of an object when the average time for one oscillation is 1.058 seconds. Round your answer to the nearest gram.

anonymous · Answer

the answer is 
1311grams

amistre64 · Answer

1.058 = (38m+16965)/10(m+5000) ; and solve for m

anonymous · Answer

how?

amistre64 · Answer

1.058 = (38m+16965)/10(m+5000) / *(m+5000)

1.058m + 1.058(5000) = 38m +16965    ; switch values to combine like terms

5290 - 16965 = 36.942m  ; /36.942

-316.03... = m  well its work if I could decipher the equation you typed

amistre64 · Answer

i dropped a 10 lol

anonymous · Answer

don't worry about the one, i got another problem similar to this one, but dont got the answer,

anonymous · Answer

A model for the data is given by the following. 
 

Use the model to approximate the mass of an object when the average time for one oscillation is 1.031 seconds. Round your answer to the nearest gram. 
t=35m+16965/10(m+5000)

amistre64 · Answer

1.058 = (38m+16965)/10(m+5000) / *(10m+50000) 

10.58m + 1.058(50000) = 38m +16965

52900 - 16965 = 27.42m

1310.53... = m

anonymous · Answer

yeah, got the with the calculator

anonymous · Answer

should it not be 10m? in the first step? after you distribute the 10?

amistre64 · Answer

1400.77... is what I get with the new one

amistre64 · Answer

teh old one:

1.058(10m) = 10.58m

anonymous · Answer

no, you had 10(m+5000)