Alphonse (point A) is over a 2500-meter landing strip in a hot-air balloon. At one end of the strip, Beatrice (point B) sees Alphonse with an angle of elevation measuring 39°. At the other end of the strip, Collette (point C) sees Alphonse with an angle of elevation measuring 62°. a. What is the distance between Alphonse and Beatrice? b. What is the distance between Alphonse and Collette? c. How high up is Alphonse?
You can find angle A. 180 degrees minus (angle B + angle C). Once you have that angle, use the same technique as previous problems.
wait what that support to mean...
how to set the problem with 82
82?
Let D be the point on the earth' s surface directly below the ballon. Let x be AD, the height of the balloon and y be the distance between B and D. Then the two equations below can be derived from the given information:\[\left\{\frac{x}{y}=\text{Tan}[39/180 \pi ],\frac{x}{2500-y}=\text{Tan}[62/180 \pi ]\right\} \]There are two solutions, x and y. Only x is required: x = 1415.14 and is the answer to question C. Question A:\[\text{AB}=1415.14\text{ Csc}\left[\frac{13 \pi }{60}\right]=2248.68 \]Question B answer:\[\text{AC}\text{=}1415.14\text{ Csc}\left[\frac{31 \pi }{90}\right]=1602.75 \]
so that mean tan-1(39/180pi)?
what Csc?
OK, Robotey was showing you another way, but I remember you are still in high school. So, as I was saying you don't have angle A. But all triangles are 180, so 180-39-62 would give you A.
you just wonder why 82 because i add 39 and 62 which 101 the subract it then got 79......oop my bad it 79
OK, you know, distance Alphonse and Beatrice is line c, (Sin 62)/c=(Sin 79)/2500
can i crosss it or not
Any way you like, just get c=....
i got 2248.62
Good, same as Robotey, different method.
that would be easy for me
omg this problem took me forever alot of mistakes lol i finally got it to work this is probably the long way
if you want to make fun of me chaguanas,you can
I would, only there is nothing coming up on your attachment. How would you handle the height of Alphonse?
the attachment isn't working? :(
nada
that too hard to rerember this
try again if it doesn't work i will try to explain
Still nothing. Hikari, you got b and c?
the height is the first thing i found...
not really
Distance between Alphonse and collette is line b. (Sin A)/a=(Sin B)/b
so how i am able to find the angle
You have everything, except line b. So put in all info and solve for b.
so i used the pytagrean thm twice i called the point that she began her elevation G k? (this means BG+GC=2500 so we have AG^2+BG^2=AB^2 AG^2+GC^2=AC^2 solved both of the for AG^2 and set them equal AB^2-BG^2=AC^2-GC^2 AB^2-AC^2=BG^2-GC^2 AB^2-AC^2=(BG+GC)(BG-GC) AB^2-AC^2=(2500)(BG-GC) then i went to the side to get every term in terms of AG AB=AG/sin39 so AB^2=AG^2/sin^2(39) and AC=AG/sin62 so AC^2=AG^2/sin^2(62) also BG=AG/tan39 and GC=AG/tan62 then i got \[AG^2(\frac{1}{\sin^239}-\frac{1}{\sin^2(62)})-AG(2500)(\frac{1}{\tan39}-\frac{1}{\tan62})=0\]
So AG cannot be zero so AG=1415.142464
so i am still using 39 and 62
the rest easy AC=1415.142464/sin62 AB=1415.142464/sin39
Yes, Hikari. Wow, Myininaya, a lot of work.
yes u know thats why i was hoping the attachment would work lol
i have three other attemps like this but they are in the garbage because i kept making an error then finally PERFECTO! lol
Great. Now if we can find the elementary method to show hikari.
now i know c is 2248.7 so i can use that
i think my way is elementary but long However I think the problem could have been solved with less steps
Yes, Hikari, you can use c if you like.
so sin62/B=sin39/2248.7
Mix up (Sin 39)/b=(Sin 62)/2248.7
and then with that fix you will have the same answer as rob and i
i think you have one more leg remaining that you need to find the length do you know law of cosines?
i got 1602.79 so can i round it or not
i assume rounding is okay i believe it is impossible to have the exact value anyways
so now the c question
Ok, if you draw a line from A to bottom, it makes a right angle. So you can use sin. Sin B=Alphonseheight/2248.7. Solve for Alphonse height.
sinB=A/2248.7
sinB=A/2248.7
Yeah, but call it something else don't call it A. Let's call it p. Sin 39=p/2248.7
i got 1415.10
Good! Same thing Myinaya have. Good job.
gj hirkari
thank for helping me and esay for me to remember this thank you
:)
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