Question

what is the radius of this equation: x squared plus y squared minus 14x plus 6y plus 42=0

Answer 1

4

Answer 2

Ok after completing the square you get the equations (x-7)^2+(x+3)^2=16. Take the square root of 16 which is 4. That is your radius.

Answer 3

Ok after completing the square you get the equations (x-7)^2+(x+3)^2=16. Take the square root of 16 which is 4. That is your radius.

Answer 4

x^2 + y^2 - 14x + 6y +4 = 0
x^2-14x-y^2+6y = -4
(x^2-14x + 49)-49 - (y^2-6y+9)-9 = -4
(x^2 - 14x + 49) - (y^2 - 6y + 9) = -4 + 49 + 9

Answer 5

agree with helpp1234

Answer 6

centre of circle is (-g,-f) in circle equation x^2 +y^2 +2gx+2fy+c=0
and radius =sqrt(g^2 +f^2 -c)

Answer 7

so radius = 4