Question

Parametric Differentiation

x= 2+ sec theta , y = 1+ 2tan theta

theta = pi/6 (30 degrees)

Find dy/dx and evaluate the specified value of the parameter

Answer 1

so first i differentiated and got \[2\sec ^{2}\theta/\sec \theta \tan \theta\]

Answer 2

<sec(t)tan(t),2sec^2(t)>

Answer 3

then i substituted the value in and got 3

Answer 4

is 3 correct?

Answer 5

maybe, gotta calc it :)

Answer 6

\[((2)(\sqrt{3}/2))/(\sqrt{3}/2*1/\sqrt{3})\]

Answer 7

i get 1/4

Answer 8

oki

Answer 9

i think i know where i went wrong let me check it

Answer 10

\[(\frac{2}{\sqrt{3}})^2 \div \frac{2}{\sqrt{3}}\frac{1}{\sqrt{3}}\]

Answer 11

the top maybe wrong i got the same bottom when i did it over

Answer 12

dropped a '2' :)

\[\frac{2\over3}{8\over 3}={2\over8}=1/4\]

Answer 13

give me a sec to figure it out

Answer 14

i got 8/2

Answer 15

for the top part it was 2 sec^2 theta

Answer 16

youre right, i got it flipped in me head

Answer 17

so its 4? yay!

Answer 18

its 4 :)

Answer 19

as always thank youso much for your help amistre

Answer 20

thanx for correcting my mistake ;)

Answer 21

your welcomes!