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Consider the function below. f(x) = 2x2 - 2x (a) Find f '(1).
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\[f(x)=2x^2-2x\]
2
how please show step by step
i got it to be 4
differentiate it and then put value of x
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i did that but somehow keeps getting 4..and its not what the textbook shows me
Taking your function f(x)=\[2x^2-2x\] and differentiating it, you get: f'(x)=\[4x-2\]. Plugging in 1 you get f'(1)=\[4(1)-2\] or 2
so you dont use the lim as h approaches o f(a+h)-f(a)/h
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