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Mathematics 12 Online
OpenStudy (anonymous):

Consider the function below. f(x) = 2x2 - 2x (a) Find f '(1).

OpenStudy (anonymous):

\[f(x)=2x^2-2x\]

OpenStudy (anonymous):

2

OpenStudy (anonymous):

how please show step by step

OpenStudy (anonymous):

i got it to be 4

OpenStudy (anonymous):

differentiate it and then put value of x

OpenStudy (anonymous):

i did that but somehow keeps getting 4..and its not what the textbook shows me

OpenStudy (anonymous):

Taking your function f(x)=\[2x^2-2x\] and differentiating it, you get: f'(x)=\[4x-2\]. Plugging in 1 you get f'(1)=\[4(1)-2\] or 2

OpenStudy (anonymous):

so you dont use the lim as h approaches o f(a+h)-f(a)/h

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