Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

log(base=1/2)of64

OpenStudy (anonymous):

\[\log_{1/2} 64\]

OpenStudy (anonymous):

1/2^x=64

OpenStudy (anonymous):

then what?

OpenStudy (anonymous):

\[\log_{1/2}64=-\log_{2}64 =-\log_{2}2^{6}=-6 \]

OpenStudy (anonymous):

oh ok.

OpenStudy (anonymous):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!