Question

Simplify:
\[(3z)^{2} (6z^{2})^{-3} \]

Answer 1

\[(3z ^{2})(6z ^{2})^{-3}=(3z ^{2})6^{-3} z ^{-6}=3*6^{-3}*z ^{-4}=z ^{-4}/108\]

Answer 2

answer is \[{1 \over 24z^{4}}\]

Answer 3

sorry your prob was (3z)^2...and i did it with 3z^2....so i got wrong...u r write..

Answer 4

can you explain how to get the answer?

Answer 5

\[(3z)^2(6z^2)^{-3}=(9z^2)/(6z^2)^3=\frac{9z^2}{216z^6}=1/24z^4\]

Answer 6

okay. okay... i'm still trying to grasp this

Answer 7

wait... it's not making sense. why divide on the second step?

Answer 8

where did you get 216z^6 on the third step?

Answer 9

a^-x=1/(a^x) do u know that rule?

Answer 10

nope. haa

Answer 11

(6z^2)^3=6^3z^6=216z^6

Answer 12

okay i see where the divde comes from. the negative exponent.