Question

pls help..
the value of x when 2^(3x + 3) = 2^(3x + 1) + 48 is true
a. 1
b. 3/2

Answer 1

2^(3x+3)-64=2^(3x+1)-16
so now assume the equation is true for both LHS = RHS =0
2^(3x+3)=64
x=1;
2^(3x+1)=16
x=1;
so the answer will be x=1;

Answer 2

how did u get 64 & 16??pls tell me...

Answer 3

just by randomly looking at the problem.. i'm sorry i cant come up with anything definite 2^6=64 and 2^4=16 and 64-16=48 so..
You could just substitute and arrive at the answer easily...

Answer 4

okie...tnx :)

Answer 5

assume the equation is true for both LHS = RHS =0
LHS: 2^(3x+3)=64
2^(3x+3)= 2^6
implies 3x+3=6 (since base is equal)
equating 3x+3=6, we get x=1
similarly try for RHS and give me the answer

Answer 6

k...got it ..thank u..:)