Question

condense this to a single quantity: 1/2lnX +ln(x+3)-ln(x^2 +1)
thanks.

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

This appears to become a quadratic equation

Answer 3

really? well im not sure because its logarithms and u need to condense it.

Answer 4

how did you get that?

Answer 5

well it is wrong, so don't write it!

Answer 6

i made a mistake

Answer 7

oh i see could you please explain it to me?

Answer 8

\[\frac{1}{2}\ln(x)=\ln(\sqrt{x})\]

Answer 9

because
\[\ln(x^n)=n\ln(x)\]

Answer 10

here i am going from the right hand side to the left hand side.

Answer 11

\[\frac{1}{2}\ln(x)=\ln(x^{\frac{1}{2}})=\ln(\sqrt{x})\]

Answer 12

then we use
\[\ln(ab) = \ln(a)+ln(b)\] again from the right to the left.

Answer 13

so we get
\[\ln(\sqrt{x})+\ln(x+3)=\ln(\sqrt{x}(x+3))\]

Answer 14

then we use \[\ln(a)-\ln(b)=\ln(\frac{a}{b})\]

Answer 15

to get
\[\ln(\sqrt{x}(x+3))-\ln(x^2+1)=\ln(\frac{\sqrt{x}(x+3)}{x^2+1})\]

Answer 16

i made a mistake on the first try and wrote \[\frac{1}{2}\ln(x)=\ln(x^2)\] which is wrong

Answer 17

there now i deleted it. hope the steps are clear

Answer 18

ohhh no i understand thanks so much!!:]

Answer 19

welcome!