Can somebody please explain how to find the slope of the line determined by the following equation, without graphing it on paper? 3x=4y-2 I need a formula explained to be step by step, all the way to the end.
Finding the slope is very simple. First, solve for y in terms of x. Then look at the coefficient on the x variable.. This is the slope.
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don't understand the 'solve for y in terms of x'...
Basically you want to get y by itself on one side of the equal sign.
I've tried just isolating y....did not get the answer I needed..
\[ay + bx + c = 0 \implies y = \frac{-b}{a}x - \frac{c}{a}\]
What did you get when you isolated the y?
3/4x+1/2. The answer key to my college textbook says it's just 3/4.
Right. Which is what I said.
Once you isolate the y, you take the coefficient on the x variable. That is your slope.
y = 3/4x+1/2 Therefore the coefficient on the x variable is 3/4 Therefore the slope is 3/4
Got it now, thanks. :)
the simplest way is just to determine 2 points from the equation; and find out how far the y moves when x moves 1 unit
3x=4y-2 ; when x =0, y = 2/4 ; when x = 1, y = 5/4 the slope is the change in y; 5/4 - 2/4 = 3/4
The amount the y moves when x moves one unit _is_ the coefficient on the x variable. ;p
yes it is :)
much easier to find then plugging in numbers ;p
easier? I agree, but simplicity is not in moving and rearranging. Just another way to accomplish it ;)
I've got to get back to my math now...thanks polpak. amistre....I use your method on other slope problems..but found it confusing on this one, glad that I now have a back-up formula. Thanks again. :)
good luck ;)
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