Question

(sec(x))(tan(x))(sin(x))

Answer 1

(tanx)^2

Answer 2

secx sinx is tanx

Answer 3

so the answer is tan^2?

Answer 4

yeah

Answer 5

okay i have another question i have tan(-x)/(sec(x)-cos(x))

Answer 6

would it be sinx or -sinx? am i on the right track?

Answer 7

-1/sinx

Answer 8

so -cscx?

Answer 9

right

Answer 10

can you explain how you got that?

Answer 11

tan(-x) = -sinx/cosx
and
secx - cosx = [1-cos^2 x]/cosx
when u divide the two you get
-sinx/sin^2 x

Answer 12

ohh okay, and they cancel out leaving you with -1/sin okay thank you. you've helped so much.

Answer 13

welcome