Question

1-(Cos^2x)/(1+sinx)

Answer 1

I don't get the question...what are you trying to ask here? what is it equal to?

Answer 2

it is \[\frac{1-cos^2(x)}{1+sin(x)}\]

Answer 3

sorry, it asks to simplify the question

Answer 4

replace
\[1-cos^2(x)\] by \[sin^2(x)\] and you will get it.

Answer 5

you get \[\frac{1-xin^2(x)}{1+sin(x)}=\frac{(1+sin(x))(1-sin(x))}{1+sin(x)}\]

Answer 6

then cancel to get
\[1-sin(x)\]

Answer 7

okay thank you

Answer 8

satellite dude can we really replace cos\(^{2}\)x just like that to sin\(^{2}\)x?
1 will be used up in the conversion..