determine the shortest distance from the point (6,3) to the line y=-2x+1
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OpenStudy (anonymous):
the shortest distance is the perpendicular distance which is 14/sqrt(5)
OpenStudy (anonymous):
two ways, calc way and thinking way
OpenStudy (anonymous):
basically we shld find the right bisector rite?
OpenStudy (anonymous):
thinking way is to realize that the line connecting the point and the other line giving the shortest distance will be perpendicular to it and therefore have slope of \[\frac{1}{2}\]
OpenStudy (anonymous):
so you have a line with slope \[\frac{1}{2}\] through (6,3). find the equation of the line and then see where they intersect by setting the two lines equal
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OpenStudy (anonymous):
the equation is
\[y-3=\frac{1}{2}(x-6)\]
\[y-3=\frac{1}{2}x-3\]
\[y=\frac{1}{2}x\]
OpenStudy (anonymous):
now solve
\[-2x+1=\frac{1}{2}x\]
OpenStudy (anonymous):
\[x=\frac{2}{5}\]
OpenStudy (anonymous):
so \[y=\frac{1}{5}\]
OpenStudy (anonymous):
then use distance formula.
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