Mathematics
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OpenStudy (anonymous):
1-(cos^(x))/(1+sin(x))
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OpenStudy (anonymous):
i need help simplifying this. i have a photo to match the problem
OpenStudy (anonymous):
OpenStudy (anonymous):
except the cos should be cos^2
OpenStudy (anonymous):
i thought i answered this. oops i was wrong sorry. numerator is
\[sin^2(x)\]
OpenStudy (anonymous):
can you see the attachment?
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OpenStudy (anonymous):
how did you get that answer?
OpenStudy (anonymous):
\[{1-\cos^2x \over 1+\sin x}?\]
OpenStudy (anonymous):
no, its 1- the entire fraction i guess cos^2x/1+sinx
OpenStudy (anonymous):
ahhhhhhhh
OpenStudy (anonymous):
so numerator is
\[1-sin^2(x)=(1+sin(x))(1-sin(x))\]
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OpenStudy (anonymous):
cancel with the denominator to get
\[1-sin(x)\]
OpenStudy (anonymous):
Oh I see. So it's \(1-\frac{\cos^2x}{1+sin x}\).
\[=1-{1-\sin^2 x \over 1+\sin x}=1-{(1+\sin x)(1-\sin x) \over 1+\sin x}=1-1+\sin x=\sin x\]
OpenStudy (anonymous):
and \[1-(1-sin(x))=sin(x)\]
OpenStudy (anonymous):
what anwar said. hi answar!
OpenStudy (anonymous):
haha thank you for your help, sorry for the confusion
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OpenStudy (anonymous):
Anwar :) .. and hi. Wow you have 517 medals satellite!