Question

I need to find the integral of x^3(x^4-4)^12.
With U=((x^4)-4)

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

((1/3)(u)^13)/13

Answer 3

do substitution:
u= x^4 - 4
so: u'=4x^3
so:\[=1/4 \int\limits_{}^{}u ^{12}du = 1/4 *1/13 *u ^{13}=1/52 *(x ^{4}-4)\]

Answer 4

So, (x^4-4)^13/39

Answer 5

oups...
it should be \[1/52 * (x ^{4}-4)^{13}\]

Answer 6

good call :))

Answer 7

Yeah, its the , but sqme otherwise

Answer 8

?

Answer 9

Lol sorry, my iPad hates this site so I can barely see it or type. Oops!