Question

A={x|x E N and 12 14 years ago

Answer 1

now before you answer

Answer 2

I have to answer if the sets are equivalnt and equal

Answer 3

equivalent*

Answer 4

for two sets to be equal they must both be subsets of each other. This means they have exactly the same elements.

Answer 5

The first is read "the set of all x such that x is an element of the natural numbers on the interval (12,17]"

Answer 6

the second is read "the set of all x such that x is an element of the natural numbers on the interval [20,25)"

Answer 7

So I did the sets first and they are
A= {12,13,14,15,16,17}
B={20,21,22,23,24}

Answer 8

12 is not included in the first

Answer 9

ok

Answer 10

strictly greater than 12

Answer 11

So they are equivalent

Answer 12

no they are not equivalent. They don't contain exactly the same elements

Answer 13

Oh I tought that would mean they have the same amount of members

Answer 14

size of a set is called cardinality

Answer 15

right

Answer 16

they have equivalent cardinality, but are not equivalent as sets

Answer 17

technically if we want to show A=B, we show A is a subset of B and B is a subset of A

Answer 18

Sets which have the same cardinal number; sets whose elements can be put into one-to-one correspondence with each other. They are equivalent. But not equal.

Answer 19

so in this case A is not equivalent or equal to B?

Answer 20

when your teacher uses the term equivalent are they talking about cardinality?

Answer 21

A and B are equivalent. But they are not equal. If equivalence has to do with the cardinality of the set. Equal has to do with the elements being the exact same. For what I remember.

Answer 22

It was my understanding he was, um its sort of difficult to undestand him, because of his accet. but by reading our text book it seems as cardinality

Answer 23

I think malevolvence is right, equivalent means there is a bijection from one set to the other. meaning a 1 to 1 and onto function that maps from one set to the other

Answer 24

equality means the elements are exactly the same

Answer 25

ok

Answer 26

so our bijection is adding 7 to each element of A to get B

Answer 27

equivalent but not equal. good thing malevolence was here to remind us about equivalence

Answer 28

yess!!

Answer 29

what course are you learning about sets in?

Answer 30

Haha, thanks vitale xD

Answer 31

The course is called "Survey of College Math"

Answer 32

I actually have to head out. I'll talk to you guys later

Answer 33

cya vitale

Answer 34

thanks care, thanks!

Answer 35

You can always hit me up for help with set stuff if you need me too (if vitale isn't on).

Answer 36

Well, anything in general xP

Answer 37

The next question was asked to write set in set bulder notation {61,62,63,64,...,89}

Answer 38

So I wrote {x|x E N amd 61≤x<90}

Answer 39

Exactly :) Or even, {x|xEZ and 61≤x<90}. Because they are all integers as well.

Answer 40

so Z is Integers?

Answer 41

Yes.
\[\mathbb{R},\mathbb{Z}^+,\mathbb{Z}^-,\mathbb{Q},\mathbb{N}\]
They are Real numbers, positive integers, negative integers, rational numbers, natural numbers respectively. Note: The positive and negative integers EXCLUDE zero.

Answer 42

right

Answer 43

\[\mathbb{Z}\] Is all integers.

Answer 44

This statement is true?
\[{1,2,5}\subset{1,2,3,4,5,6,7}\]

Answer 45

Yes. Because 1,2,5 are all in the set. In other words {1,2,5} is a subset of {1,2,3,4,5,6,7}

Answer 46

see, I'm learning! :)

Answer 47

:D

Answer 48

and there is a text tomorrow lol

Answer 49

and there is a text tomorrow lol

Answer 50

Damnnnn, well I should be able to help you with all you need :) I have to go get food soon but after that I'll be on for a while.

Answer 51

ok, I appreciate you soooo much! lol

Answer 52

what does this mean? \[\subseteq\]

Answer 53

what does this mean? \[\subseteq\]

Answer 54

Proper subset.

Answer 55

{9,1,7,3,4} is not a proper to {1,3,4,7,9} because they are not in order?

Answer 56

In a set, the order is irrelevant. If A is a subset of B, but A is not equal to B (i.e. there exists at least one element of B not contained in A), then
A is also a proper (or strict) subset of B.
So the first one is not a proper subset because they are equal.

Answer 57

why are they not equal if all members are there?

Answer 58

They are equal. But they aren't proper subsets of each other. The are subsets however. Does that make sense? Be back in 20 minutes.

Answer 59

No, ook

Answer 60

The sets are equal because every element of the first one (call it A) is in the second one (call it B). They are also equivalent because their cardinalities are the same. However, A is not a proper subset of B nor is B a proper subset of A because there is no element of A that is not in B or any element of B that is not in A. Does that help?

Answer 61

ooooh

Answer 62

yes

Answer 63

Okay, anything else? :P

Answer 64

ummm, IDK lol

Answer 65

ummm, IDK lol

Answer 66

Just post if anything comes up.