Question

find dy/dx if (y^2)-3xy+x^2+7

Answer 1

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Answer 2

implicit diff yes?

Answer 3

yes

Answer 4

take the derivative with respect to x, remembering that y is a function of x. so for example the derivative of
\[y^2\] is \[2yy'\] by the chain rule

Answer 5

i assume it is set = 0 or something yes?

Answer 6

\[y^2-3xy+x^2=7=0\]?

Answer 7

i mean \[y^2-3xy+x^2+7=7\]

Answer 8

damn

Answer 9

=0 i mean not = 7

Answer 10

you get
\[2yy' -3y - 3xy'+2x=0\]

Answer 11

then solve for y'

Answer 12

\[2yy'-3xy'=3y-2x\]
\[y'(2y-3x)=3y -2x\]
\[y'=\frac{3y-2x}{2y-3x}\]