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Mathematics 15 Online
OpenStudy (anonymous):

find a matrix M(2x2) such that AM=I. I is a identity matrix of 2x2.

OpenStudy (anonymous):

\[M=A^{-1}\]

OpenStudy (anonymous):

what is A here

OpenStudy (anonymous):

A=[7 9; 3 4] sorry for the dealy. I lost internet connection. So how do I get A^ -1

OpenStudy (anonymous):

Does that mean the inverse of a matrix?

OpenStudy (anonymous):

yh inverse only

OpenStudy (anonymous):

how do I found it? (1/det(A))*A?

OpenStudy (anonymous):

coz the determinant is equal to 1

OpenStudy (anonymous):

adj A / determinant A

OpenStudy (anonymous):

determinant of A is -1

OpenStudy (anonymous):

=> 4 -9 -3 7

OpenStudy (anonymous):

yeah. So det(A)=(28)-(27) =1

OpenStudy (anonymous):

that means that M must be equal to A.

OpenStudy (anonymous):

no... M= adjoint of A

OpenStudy (anonymous):

what is adjoint?

OpenStudy (anonymous):

and sorry the original matrix A ={{7,9},{3,4}}

OpenStudy (anonymous):

yh i took A as this only....

OpenStudy (anonymous):

adjoint: adjoint of a matrix , can be got by replacing each element of a matrix, by its cofactor..

OpenStudy (anonymous):

so you mena I should change ij by ji in the matrix

OpenStudy (anonymous):

NO. i.e transpose... i said cofactor...

OpenStudy (anonymous):

can you give me an example man. Lets use this matrix K={{1,2}, {3,4}}

OpenStudy (anonymous):

its adjoint is... 4 -2 -3 1

OpenStudy (anonymous):

how did you get that?

OpenStudy (anonymous):

I dont get it. Sorry

OpenStudy (anonymous):

Doing some research I finally got with the answer. Thanks Kishan

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