Mathematics
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OpenStudy (anonymous):
find a matrix M(2x2) such that AM=I. I is a identity matrix of 2x2.
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OpenStudy (anonymous):
\[M=A^{-1}\]
OpenStudy (anonymous):
what is A here
OpenStudy (anonymous):
A=[7 9; 3 4] sorry for the dealy. I lost internet connection. So how do I get A^ -1
OpenStudy (anonymous):
Does that mean the inverse of a matrix?
OpenStudy (anonymous):
yh inverse only
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OpenStudy (anonymous):
how do I found it? (1/det(A))*A?
OpenStudy (anonymous):
coz the determinant is equal to 1
OpenStudy (anonymous):
adj A / determinant A
OpenStudy (anonymous):
determinant of A is -1
OpenStudy (anonymous):
=> 4 -9
-3 7
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OpenStudy (anonymous):
yeah. So det(A)=(28)-(27) =1
OpenStudy (anonymous):
that means that M must be equal to A.
OpenStudy (anonymous):
no...
M= adjoint of A
OpenStudy (anonymous):
what is adjoint?
OpenStudy (anonymous):
and sorry the original matrix A ={{7,9},{3,4}}
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OpenStudy (anonymous):
yh i took A as this only....
OpenStudy (anonymous):
adjoint: adjoint of a matrix , can be got by replacing each element of a matrix, by its cofactor..
OpenStudy (anonymous):
so you mena I should change ij by ji in the matrix
OpenStudy (anonymous):
NO.
i.e transpose... i said cofactor...
OpenStudy (anonymous):
can you give me an example man. Lets use this matrix K={{1,2}, {3,4}}
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OpenStudy (anonymous):
its adjoint is...
4 -2
-3 1
OpenStudy (anonymous):
how did you get that?
OpenStudy (anonymous):
I dont get it. Sorry
OpenStudy (anonymous):
Doing some research I finally got with the answer. Thanks Kishan