Question

e^(x/10) = -y^2 + 100y

how would I make y the subject

Answer 1

add y^2 to both sides

Answer 2

does that mean "solve for y'?

Answer 3

yes, y = ..

Answer 4

then subtract e^(x/10) to both sides

Answer 5

you could treat it like a quadratic where e^x/10 is your "c" term
\[y= 50\pm \sqrt{2500 - e ^{x/10}}\]

Answer 6

y^2 = -e^(x/10) + 100y

Answer 7

and this leads to dumbcows answer,,lol

Answer 8

0 = -y^2 + 100y -e^(x/10) quadratic form of equation

Answer 9

y^2 -100y +e^(x/10) =0

Answer 10

y=(-(-100)-+sqrt(100^2 -4(1)(4e^(x/10))))/2
y=(100-+sqrt(10000-4e^(x/10)))/2
y=(50-+sqrt(2500-e^(x/10))