Question

The radius of the earth is 6370Km and the radius of mars is 3440Km. If an object weights 200N on earth, what will be the gravity on mars? Mars has a mass of 0.11 times the mass of the earth.

Answer 1

mg =200
g(mars) = GM(mars)/R(mars)^2
W(mars) = mg(mars)

Answer 2

how do you get there this expression?
g(mars) = GM(mars)/R(mars)^2

Answer 3

g of any planet is given by this formula

Answer 4

and G is a constant, isnt it?

Answer 5

if the objects mass is m and planets mass is M and radius R the force bw them is GMm/R^2
so the acceleration due to gravity on the planet is F/m = GM/R^2

Answer 6

G is the Universal Gravitational Constant

Answer 7

F=GMm/R^2

Answer 8

yes....now F/m is acceleration

Answer 9

ok

Answer 10

so now ur doing gravitation? how old r u?

Answer 11

Im helping my newphew. He is finishin high school.

Answer 12

im 22 year old.

Answer 13

and what r u studying?

Answer 14

Electronics and telecomunications. At the university. Im working on my thesis proyect. I received physics when I was in 2d semester.

Answer 15

thesis on what topic?

Answer 16

Pattern recognition :)

Answer 17

Digital signal processing

Answer 18

ohk

Answer 19

So what step should I take next? In the problem

Answer 20

W(Earth)/W(mars) = g(Earth)/g(mars) = [m(E)/m(M)] x [ R(E)/R(M)]^2 = 200/W

Answer 21

now crossmultiply and evaluate W

Answer 22

get it?

Answer 23

let me check it out

Answer 24

sorry

Answer 25

make it[R(M)/R(E)]^2

Answer 26

ok

Answer 27

what does W represent in = 200/W

Answer 28

is that the W I should isolate?

Answer 29

Weight on mars

Answer 30

yes

Answer 31

Ok

Answer 32

w=200/( [m(E)/m(M)] x [ R(E)/R(M)]^2 )
Am I right?

Answer 33

R(m) /R(e)

Answer 34

insteade of r(e) by r(m)

Answer 35

you mean isolating and simplifying, I get
w=r(e)/r(m)

Answer 36

confused

Answer 37

no no....i mean replace the [R(e)/R(m)]^2 by [R(m)/R(e)]^2..rest is same

Answer 38

in the first equaton?

Answer 39

In this equation?
W(Earth)/W(mars) = g(Earth)/g(mars) = [m(E)/m(M)] x [ R(E)/R(M)]^2 = 200/W

Answer 40

W(Earth)/W(mars) = g(Earth)/g(mars) = [m(E)/m(M)] x [ R(M)/R(E)]^2 = 200/W

Answer 41

from this equation I isolate W. and I should get the answer. Right?

Answer 42

yes

Answer 43

Ok thanks:)

Answer 44

This is my email. emunrradtvamg@hotmail.com. If you have facebook or simething related, add me. Him, I have to leave now, I have to go home now. Im so angrey. Hope I can see you soon

Answer 45

hungry, sorrry lol