Question

differentiate the following function
y=(9x^2)+4(sqrt x)/(3x)

Answer 1

i got the answer to be (18x+2/(sqrt x)/3

Answer 2

not sure if thats right

Answer 3

the derivative of first term is 18x and 4(sqrt x)/(3x) is differentiated by the quotient
rule whch

is d(u/v) =[ (v* du/dx ) -( u*dv/dx)] / v^2

where u and v are functions of x

did u use this?

Answer 4

oh hold on an easier way may be to do the division first

4(sqrt x)/(3x) = (4/3) x^(-0.5)

in which case dy/dx = -2/3 x^ -1.5
= -2 / (3x^(3/2)

so final answer = 18x -2 / (3x^(3/2)

Answer 5

still there rmal?

Answer 6

yes..but im still trying to understnd the function because my java not working right

Answer 7

use y=9x^2 +(4x^1/2)/3x
=9x^2 +(4x^-1/2)/3
dy/dx=18x-(4/6)x^-3/2
dy/dx=18x-(2/3)x^-3/2 or
dy/dx=18x-(2/3x^3/2)

Answer 8

looks ok then- 2 people with same answer

Answer 9

yeah lol.....

Answer 10

my textbook answer shows otherwise

Answer 11

oh !!! - u sure? what answer does it gave?

Answer 12

i meant my online course says another but i plug in the solutions the step by step by still wrong...i think it might be the 3x^(3/2)

Answer 13

yes thats it..thats our answer..lol

Answer 14

ours is definitely correct - i checked it with some software i have (verify)