Question

An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.

Compute the probability of each of the following events:

Event : The sum is greater than 5 .
Event : The sum is divisible by 5.

Answer 1

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Answer 2

2 rolls are 36 possible outcomes; so it a/36

1,5; 5,1; 2,4; 4,2; 3,3 are all possible events that result in greater then 5

5/36

Answer 3

the possible sums are 2 thru 12; so how many are divisible by 5?

5/5, 10/5 to make it 2/36

Answer 4

@amistre64
I feel u r making a mistake
P(sum greater than 5) = 26/36 = 13/18
and
P(sum divisible by 5) = 7/36

Answer 5

U can check by writing all possible 36 outcomes

Answer 6

mistake? me? thats highly possible ;)

Answer 7

1,5; 5,1; 2,4; 4,2; 3,3 ...... youre right, I stopped counting for some reason lol

Answer 8

We all make mistakes every now n then, today it was your turn :)

Answer 9

1,5 1,6
2,4 2,5 2,6
3,3 3,4 3,5 3,6
4,2 4,3 4,4 4,5 4,6
5,1 5,2 5,3 5,4 5,5 5,6
6,1 6,2 6,3 6,4 6,5 6,6

26/36

Answer 10

Correct !!!!!

Answer 11

By the way, are u a teacher??