Question

[(y^2)x(z^(3/4))]^-1/2 don't use negative exponents

Answer 1

dont use negative exponents in the answer

Answer 2

Recall that
\[(a^xb^y)^c = a^{cx}b^{cy}\]
So you can multiply your exponents by the -1/2

Answer 3

Then also recall that:
\[a^{-b} = \frac{1}{a^b}\]

Answer 4

yes

Answer 5

So did you try it yet?

Answer 6

im guessing its 1/yz^3/8

Answer 7

That's right.

Answer 8

You shouldn't be guessing though ;p