Pls help...evaluate 10^x when x = lg 5...thank you
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I am assuming it is log base 10
yes...is log base 10
if you have base to the log of that base it cancel
\[x^{\log_{x}b }=b\]
what about if x = lg (lg 5)?
still base 10?
yes
You could just evaulate it using calculator
gotta show workings
5
10^log[5]=ans log[10^log[5]]=log[ans] log[5]log[10]=log[ans] log[10]=1 log[5]=log[ans] get rid of log 5=answer
i understood now but what about if x = lg (lg 5)?
10^x=log[5]
10^((10)^x)=5
then use x=logy, where y=log5 10^x=y=log5
did u get that kwoky
im still trying to figure out ...
ok, w/c one? the latter or the first q?
the latter...cos i don't understand how can both answers turn out to be 5
evaluate 10^x when x = log5 10^x=10^log5 = 5
This one I understood but when x = log ( log 5), I don't quite understand.
x = log ( log 5) then use x= log ( y ), where y=log5 10^x=10^logy =y =log5
understood better?
my pc kept hanging up/...lol
erm....I think I'm quite dumb with log...still confused. I still think that with 10^lg ( lg 5), the 10^lg will be cancelled thus the ans should be lg 5 instead of 5.
10^logy = y
but since there is two log..thus shouldn't the 1st log be written off with the 10, therefore answer should left with 2nd log?
therefore 10^log(log5) =log5
yup...ans should be log 5 then.
10^log(M) =M 10^log555 =555
ok...thanks mark !
ok wc kworky..good luck post some more q. so that you can practice solving them
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