Question

how do u factor this question:
2w(y-2z)-x(y-2z)

Answer 1

(y-2z)(2w-x)

Answer 2

It is (y-2z) (2w - x) this is by taking the common factor (y-2z) from both

Answer 3

how did u get that

Answer 4

by taking the common factor

Answer 5

They're both multiplied by the common factor

Answer 6

can u show me step by step, im confused on factoring equations

Answer 7

Here we use the distributive law in reverse

Answer 8

distributive law says a (b+d) = ab + ad

This can also be put as ab + ad = a (b+d)

Understood now??

Answer 9

yes thank u

Answer 10

but how to do u get the answer since the question has ( )

Answer 11

when u have more than one number i.e. it is two terms then u have to put brackets
so in your case a(b) + a(d) = a (b+d)

Answer 12

oh ok, thanks again

Answer 13

Since (y-2z) is common to both treat it as a and 2w as b and -x as d

Answer 14

and how about x^2-2x+3x-6
how do u do that one

Answer 15

Here in the first two terms x^2 and -2x we have common factor x
so they can be combined using distributive law as x(x -2)

Now we have to resolve the last two terms so that we get (x-2) in the bracket
this can be done as follows +3 (x-2)

Answer 16

So the question become x(x-2) +3 (x-2)
We find (x-2) is common so it becomes (x-2) (x+3)

Got it??

Answer 17

oh ok, thanks

Answer 18

Where r u located sanasaj???

Answer 19

y

Answer 20

just curious, I am frm Delhi, india

Answer 21

oh ok, im from the US

Answer 22

U going to school or home-study??

Answer 23

home-study

Answer 24

I think u shud buy books by R. D. Sharma - an Indian author - for maths. I think u must b in 7th or 8th standard